Conveying objects up or down via inclined or declined belt conveyors is very common. Probably teh most asked question involves determining the maximum angle an object will convey. This varies from product-to-product depending on the configuration of the object being moved and on the carrying surface of the object. One package 12″ Wide x 12″ High x 24″ Long with a rough bottom conveying surface will convey at a higher grade than an object the exact same size with a smooth or slick bottom conveying surface.
Due to limited floor space and other conditions, an incline unit may require a greater angle than is recommended for the application. Some possible solutions include using a slided bed conveyor with a cleated belt. In this case, center drive, nose-over and integral feeders must be removed from the unit. Another possible solution is to explore specialty incline belts such as the “sticky top” belt which may provide an improved carrying friction surface. Still yet, a Roach continous vertical conveyor or reciprocating vertical conveyor would another option to explore especially if floor space is very limited. Rates as high as 35 packages per minute are possible with a continous vertical conveyor.
CAUTION: Excercise extreme caution when conveying plastic tote pans. These objects often have “slick” bottom conveying surface and will require additional consideration. Consult Material Flow for questions or specific requests.
Maximum Angle of Incline Formula
The following formula is a useful tool for quick reference in determining maximum angle of incline. Remember, when this formula is completed, the resulting answer requires additional consideration to ensure that the angle chosen will convey the specific product considering its bottom conveying surface. The formula yields the tangent of the incline application.
Tan “B” = 1/3 (Package Length) / Package Height